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LOL, do you know what the possibility is of you sucessfully getting a CD-Key? 26 (letters) + 10 (numbers) = 36, with a 20-digit CDKey.
36_P_20 = 36! / (36 - 20)! = 36! / 16! = 1:17,779,336,731,917,059,409,510,400,000 chance.
Let's assume that there are 100 million active CDKeys (obviously there are much less, but I'm being generous.
1:17,779,336,731,917,059,409,510,400,000 - 100,000,000 = 17,779,336,731,917,059,409,410,400,000 means you have one in 17 OCTILLION chance of guessing a correct CD-Key. Let's say you have a macro that types a 20 digit cd-key in one second, you have one second of server lag when submitting the key, and it takes one second to erase the key. So we have 3 seconds per each key test. It would take you 31,321,059,309,910,823 CENTURIES, on average, to guess one CD-Key.
(17,779,336,731,917,059,409,409,400,000 / 3 / 60 / 60 / 60 / 24 / 365 / 100)
Have fun.
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